Compute equivalent resistance for resistors in series and in parallel, and apply the power formulas within a multi-resistor circuit.
Resistors in series (one after another, along a single path) add directly: R_eq = R1+R2+R3+.... The SAME current flows through every resistor in a series circuit (there is only the one path for it to take), while the total voltage divides across them in proportion to each resistor's share of the total resistance. Resistors in parallel (side by side, offering multiple paths) combine differently: 1/R_eq = 1/R1 + 1/R2 + .... Every resistor in parallel gets the SAME full voltage (each is connected directly across the same two points), while current divides among the paths, with more current flowing through lower-resistance branches. Adding another parallel path always DECREASES the equivalent resistance below even the smallest individual resistor, since it opens up an additional route for current to take.
Power dissipated by any resistor can be found three equivalent ways -- P=I*V=I^2*R=V^2/R -- so pick whichever form matches the two quantities already known for that particular resistor. This matters in real wiring: household outlets are deliberately connected in PARALLEL, so every device receives the full outlet voltage independently, and so that one device failing (or being unplugged) does not interrupt power to the others -- unlike old-style series holiday lights, where a single burnt-out bulb could darken (or even break) the entire string.
Mastery looks like: They correctly compute equivalent resistance for resistors in series or in parallel, and find the current, voltage, or power for each resistor in a simple combination circuit.
Common stumbles: Adding parallel resistances directly instead of using the reciprocal formula; assuming voltage divides across parallel branches the way it does in series (each parallel branch actually receives the full voltage).