Compute the sum of a polygon's interior angles, and find interior or exterior angle measures of a regular polygon in either direction.
Any polygon's interior angles can be found by chopping it into triangles from one vertex: a polygon with n sides splits into (n-2) triangles, and since each triangle contributes 180 degrees, the SUM of a polygon's interior angles is (n-2) * 180 degrees. A quadrilateral (n=4) splits into 2 triangles, giving 360 degrees; a pentagon (n=5) splits into 3 triangles, giving 540 degrees, and so on.
Exterior angles behave more simply: no matter how many sides a polygon has, its exterior angles (one per vertex, turning the same direction all the way around) always add up to exactly 360 degrees -- one full turn walking the perimeter. For a REGULAR polygon (all sides congruent, all angles congruent), dividing evenly gives a formula for a single angle: each interior angle is (n-2)*180 / n, and each exterior angle is 360 / n. Since an interior angle and its exterior angle form a linear pair, checking that the two you compute add to 180 is a fast built-in error check.
Mastery looks like: They compute the sum of interior angles, and the measure of each interior or exterior angle of a regular polygon, in both directions.
Common stumbles: Using n instead of (n-2) in the interior angle sum formula; forgetting the exterior angle formula always uses 360, not the interior angle sum.
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