Graph quadratic functions from standard form, identifying the y-intercept, axis of symmetry, and vertex.
Every function you graphed in term one made a straight line. A quadratic, y = ax² + bx + c, makes a curve called a parabola - a smooth U-shape (or upside-down U) caused entirely by that squared term. The sign of a decides which way it opens: positive a opens upward like a bowl (with a lowest point), negative a opens downward like a dome (with a highest point).
Standard form hands you two facts for free: c is the y-intercept (plug in x = 0 and everything with an x disappears), and the sign of a tells you the direction. The vertex - the parabola's tip, its minimum or maximum - sits on the axis of symmetry, the vertical line x = -b/(2a) that splits the parabola into two mirror-image halves. Find that x-value, substitute it back in for the matching y, and you have located the single most important point on the graph.
Mastery looks like: They can find the y-intercept, axis of symmetry, and vertex of any y = ax² + bx + c, and state the opening direction from a alone.
Common stumbles: Forgetting the negative sign in x = -b/(2a); mixing up the vertex's x-coordinate with the y-intercept.