Multiply a 1-digit number by a 3-digit number using an area model with three partial products.
The same idea from last week just grows by one more piece. Split the 3-digit number into hundreds, tens, and ones, multiply each part by the 1-digit number, then add all three partial products.
If one of the digits happens to be a zero, that partial product is simply zero, but the place still has to be accounted for.
Mastery looks like: They multiply a 1-digit number by a 3-digit number using three partial products and add them correctly.
Common stumbles: Dropping the partial product for a zero digit instead of keeping it as a placeholder; misaligning place value when adding three partial products.
See it visually
Interactive, spoken-aloud tools that show this idea in motion.