Tenth Grade · Science · week 30

Concentration: molarity and dilution

Calculate the molarity of a solution, calculate the mass or moles of solute needed to prepare a solution of a given molarity, and solve dilution problems using M1V1 = M2V2.

Molarity (M) is the most common way chemists measure concentration: the number of moles of solute dissolved per liter of total solution, M = moles of solute / liters of solution. A 2.0 M solution of NaCl means every liter of that solution contains 2.0 moles of dissolved NaCl -- and this measurement, unlike a simple ratio of solute to solvent, is defined by the volume of the ENTIRE solution, solute and solvent together.

Molarity connects directly to mole and mass calculations from earlier this semester: moles of solute = M x liters of solution, and from there, grams of solute = moles x molar mass, exactly as before.

Dilution is the process of adding more solvent to a concentrated ("stock") solution to lower its concentration, without changing the actual amount (moles) of solute present -- only the volume increases, spreading the same amount of solute more thinly. Since moles of solute stays constant through a dilution, M1V1 = M2V2 (concentration times volume before dilution equals concentration times volume after), where M1 and V1 describe the concentrated stock solution and M2 and V2 describe the final, diluted solution.

📋 For the teacher
Teach it (10–15 min):
  • Connect molarity directly back to the mole-and-molar-mass unit from a few weeks ago: this week is that same skill with one more step (dividing by volume) layered on top, not a brand new topic from scratch.
  • For dilution, use a real kitchen analogy: making weaker lemonade by adding more water to the same amount of lemonade concentrate changes how strong it tastes (concentration) without changing how much actual lemonade flavoring (solute) is in the pitcher.
  • Make sure units of volume match on both sides of M1V1=M2V2 (both in L, or both in mL) before solving -- a very common error is mixing L and mL within the same dilution problem.
  • If measuring spoons and cups are available, a genuinely hands-on (non-hazardous) version of this idea: make a very concentrated sugar-water solution, then have them calculate how much water to add to cut the concentration in half, and test whether the diluted result tastes about half as sweet.
Talk about it:
  • What does molarity actually measure?
  • What changes and what stays the same when a solution is diluted?
  • Why must volume units match on both sides of a dilution calculation?

Mastery looks like: They correctly calculate molarity from moles and volume, calculate the mass or moles of solute needed for a target molarity, and solve dilution problems using M1V1 = M2V2.

Common stumbles: Dividing moles by milliliters instead of converting to liters first; assuming moles of solute change during a dilution when only the volume actually changes.

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