Apply the extra diagonal properties of rectangles and rhombuses, and place squares within the parallelogram hierarchy.
Three special parallelograms each add one extra condition on top of everything a parallelogram already guarantees. A rectangle is a parallelogram with four right angles, and that extra condition earns one new property: its diagonals are congruent, on top of bisecting each other. A rhombus is a parallelogram with four congruent sides, and it earns two new properties: its diagonals are perpendicular to each other, and each diagonal bisects a pair of opposite vertex angles.
A square is both a rectangle and a rhombus at once -- four right angles AND four congruent sides -- so it inherits every property from both families. This creates a hierarchy: every square is a rectangle and a rhombus, every rectangle and every rhombus is a parallelogram, but the reverse is not true -- a generic parallelogram or rectangle is not automatically a rhombus or a square.
Mastery looks like: They correctly apply the extra properties of rectangles (congruent diagonals) and rhombuses (perpendicular diagonals, diagonals bisecting vertex angles), and place squares, rectangles, rhombuses, and parallelograms correctly within the hierarchy.
Common stumbles: Assuming every parallelogram has congruent or perpendicular diagonals instead of only the special cases; assuming a rhombus or rectangle is automatically a square.