Tenth Grade · Math · week 17

Special segments and points of concurrency in triangles

Identify the perpendicular bisector, angle bisector, median, and altitude of a triangle, and apply the properties of their points of concurrency.

Four special segments live inside every triangle, and each family of three meets at one point of concurrency. A perpendicular bisector of a side passes through its midpoint at a right angle; the three perpendicular bisectors of a triangle meet at the circumcenter, equidistant from all three VERTICES (the center of the circumscribed circle through all three vertices). An angle bisector splits a vertex angle in half; the three angle bisectors meet at the incenter, equidistant from all three SIDES (the center of the inscribed circle touching all three sides).

A median connects a vertex to the midpoint of the opposite side; the three medians meet at the centroid, the triangle's balance point. The centroid divides every median in a fixed 2:1 ratio, vertex-to-centroid compared to centroid-to-midpoint. An altitude drops from a vertex perpendicular to the line containing the opposite side; the three altitudes meet at the orthocenter, which -- unlike the incenter and centroid -- can fall OUTSIDE the triangle when the triangle is obtuse (the circumcenter can fall outside an obtuse triangle too).

📋 For the teacher
Teach it (10–15 min):
  • Build a reference chart: four segment names, four point-of-concurrency names, and the ONE defining equidistance or ratio fact for each -- review it like vocabulary until automatic.
  • Actually balance a cardboard triangle on a pencil tip at its centroid (found by intersecting two medians) to make the "balance point" fact tangible.
  • Draw one obtuse triangle together and locate all four points of concurrency on it, so the circumcenter and orthocenter can be SEEN landing outside while the incenter and centroid stay inside.
  • For the centroid ratio, always ask "which piece is longer, vertex-to-centroid or centroid-to-midpoint?" before computing -- the 2 always goes with the vertex side.
Talk about it:
  • Why does the circumcenter end up equidistant from the vertices instead of the sides?
  • Why might an engineer care about a triangular brace's centroid specifically?
  • Why do the incenter and centroid always stay inside the triangle, no matter its shape?

Mastery looks like: They correctly match each special segment to its point of concurrency and defining property, and apply the equidistance facts and the 2:1 centroid ratio to solve for unknown lengths.

Common stumbles: Mixing up which point is equidistant from vertices (circumcenter) versus sides (incenter); applying the centroid ratio backwards.

Homework for this lessonType it, write it with a stylus, or print it for pencil & paper.open →
Records attendance + 15 min of Math for this learner.
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